test

src/leecode/javascript/3227.字符串元音游戏.js

@@ -0,0 +1,31 @@
+/*
+ * @lc app=leetcode.cn id=3227 lang=javascript
+ * @lcpr version=
+ *
+ * [3227] 字符串元音游戏
+ */
+
+// @lc code=start
+/**
+ * @param {string} s
+ * @return {boolean}
+ */
+var doesAliceWin = function (s) {
+  // 字符串为空,小红先手无法移除直接盼负
+  // 判断字符串中的元音字母个数
+  // 若为奇数,小红可直接扣光,赢;
+  // 若为偶数小红移除奇数个后剩余必是奇数个,这样小明操作奇数-偶数必是奇数,小红赢,所以只要有元音字母能让小红第一次可操作就能赢
+  return [...s].some(c => 'aeiou'.includes(c));
+};
+// @lc code=end
+
+/*
+// @lcpr case=start
+// "leetcoder"\n
+// @lcpr case=end
+
+// @lcpr case=start
+// "bbcd"\n
+// @lcpr case=end
+
+ */

src/leecode/javascript/7.整数反转.js

@@ -0,0 +1,45 @@
+/*
+ * @lc app=leetcode.cn id=7 lang=javascript
+ * @lcpr version=
+ *
+ * [7] 整数反转
+ */
+
+// @lc code=start
+/**
+ * @param {number} x
+ * @return {number}
+ */
+var reverse = function (x) {
+  const MAX_INT_32 = Math.pow(2, 31) - 1;
+  const MIN_INT_32 = -Math.pow(2, 31);
+  let ret = 0;
+  while (x != 0) {
+    ret = ret * 10 + (x % 10);
+    if (ret > MAX_INT_32 || ret < MIN_INT_32) {
+      return 0;
+    }
+    x = Math.trunc(x / 10);
+  }
+  return ret; 
+};
+// @lc code=end
+
+/*
+// @lcpr case=start
+// 123\n
+// @lcpr case=end
+
+// @lcpr case=start
+// -123\n
+// @lcpr case=end
+
+// @lcpr case=start
+// 120\n
+// @lcpr case=end
+
+// @lcpr case=start
+// 0\n
+// @lcpr case=end
+
+ */